Gmurman. Probability Theory Problem Book. Problem 11

Replenishment date: 29.06.2014
Content: 011.jpg (106.75 KB)
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Description
In the box there are 10 identical parts marked with numbers 1, 2,…, 10. Six parts were taken at random. Find the probability that among the extracted parts will be: a) part No. 1; b) parts No. 1 and No. 2.

Ответ: P(A)=3/5=0,6; P(B)=1/3=0,333
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